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यदि tanθ.cos60° = $\frac{\sqrt{3}}{2}$ हो, तो 𝒔𝒊𝒏(𝜽-15°) का मान है -

1
$\frac{\sqrt{3}}{2}$
2
$\frac{1}{2}$
3
1
4
$\frac{1}{\sqrt{2}}$

Answer:- 4

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