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Kruti took a loan at simple interest rate of 6 p.c.p.a. in the first year and it increased by 1.5 p.c.p.a. every year. If she pays Rs. 8190 as interest at the end of 3 years, what was her loan amount ?

1Rs. 35400
2Rs. 36000
3Rs. 36800
4None of these

Answer:- 1

Explanation:-

Solution:

Let the loan amount be Rs. x

\begin{aligned} Then, \\ \Rightarrow \frac{6 x}{100} + \frac{7.5 x}{100} + \frac{9 x}{100} = 8190 \\ \Rightarrow 22.5 x = 819000 \\ \Rightarrow x = 36400. \end{aligned}

$\eqalign{ & {\text{Then,}} \cr & \Rightarrow \frac{{6x}}{{100}} + \frac{{7.5x}}{{100}} + \frac{{9x}}{{100}} = 8190 \cr & \Rightarrow 22.5x = 819000 \cr & \Rightarrow x = 36400. \cr}$

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", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

Let the loan amount be Rs. x

\begin{aligned} Then, \\ \Rightarrow \frac{6 x}{100} + \frac{7.5 x}{100} + \frac{9 x}{100} = 8190 \\ \Rightarrow 22.5 x = 819000 \\ \Rightarrow x = 36400. \end{aligned}

$\eqalign{ & {\text{Then,}} \cr & \Rightarrow \frac{{6x}}{{100}} + \frac{{7.5x}}{{100}} + \frac{{9x}}{{100}} = 8190 \cr & \Rightarrow 22.5x = 819000 \cr & \Rightarrow x = 36400. \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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