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If x(x + y + z) = 20, y = (x + y + z) = 30 & z(x + y + z) = 50, then the value of 2(x + y + z) is?

120
210
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418

Answer:- 1

Explanation:-

Solution:

\begin{aligned} Put (x + y + z) = 10 \\ x = 2 \\ y = 3 \\ z = 5 \\ x (x + y + z) = 20 \\ \Leftrightarrow 2 (10) = 20 \\ \Leftrightarrow 20 = 20 \\ Similarly other will satisfied, \\ So, value of 2 (x + y + z) \\ = 2 (10) \\ = 20 \end{aligned}

$\eqalign{ & {\text{Put }}\left( {x + y + z} \right) = 10 \cr & x = 2 \cr & y = 3 \cr & z = 5 \cr & x\left( {x + y + z} \right) = 20 \cr & \Leftrightarrow 2\left( {10} \right) = 20 \cr & \Leftrightarrow 20 = 20 \cr & {\text{Similarly other will satisfied,}} \cr & {\text{So, value of 2}}\left( {x + y + z} \right) \cr & = 2\left( {10} \right) \cr & = 20 \cr}$

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", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} Put (x + y + z) = 10 \\ x = 2 \\ y = 3 \\ z = 5 \\ x (x + y + z) = 20 \\ \Leftrightarrow 2 (10) = 20 \\ \Leftrightarrow 20 = 20 \\ Similarly other will satisfied, \\ So, value of 2 (x + y + z) \\ = 2 (10) \\ = 20 \end{aligned}

$\eqalign{ & {\text{Put }}\left( {x + y + z} \right) = 10 \cr & x = 2 \cr & y = 3 \cr & z = 5 \cr & x\left( {x + y + z} \right) = 20 \cr & \Leftrightarrow 2\left( {10} \right) = 20 \cr & \Leftrightarrow 20 = 20 \cr & {\text{Similarly other will satisfied,}} \cr & {\text{So, value of 2}}\left( {x + y + z} \right) \cr & = 2\left( {10} \right) \cr & = 20 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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