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If (x - 2)(x - p) = x² - ax + 6, then the value of (a - p) is?

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Answer:- 1

Explanation:-

Solution:

\begin{aligned} (x - 2) (x - p) = x^{2} - a x + 6 \\ x^{2} - (2 + p) x + 2 p = x^{2} - a x + 6 \\ Comparision the cofficients \\ 2 + p = a \\ 2 p = 6 \\ \Leftrightarrow p = 3 \\ 2 + 3 = a \\ \Leftrightarrow a = 5 \\ Then , \\ p = 3, a = 5 \\ a - p = 5 - 3 \\ \Leftrightarrow a - p = 2 \end{aligned}

$\eqalign{ & \left( {x - 2} \right)\left( {x - p} \right) = {x^2} - ax + 6 \cr & {x^2} - \left( {2 + p} \right)x + 2p = {x^2} - ax + 6 \cr & {\text{Comparision the cofficients}} \cr & 2 + p = a \cr & 2p = 6 \cr & \Leftrightarrow p = 3 \cr & 2 + 3 = a \cr & \Leftrightarrow a = 5 \cr & {\text{Then , }} \cr & p = 3,{\text{ }}a = 5 \cr & a - p = 5 - 3 \cr & \Leftrightarrow a - p = 2 \cr}$

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", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} (x - 2) (x - p) = x^{2} - a x + 6 \\ x^{2} - (2 + p) x + 2 p = x^{2} - a x + 6 \\ Comparision the cofficients \\ 2 + p = a \\ 2 p = 6 \\ \Leftrightarrow p = 3 \\ 2 + 3 = a \\ \Leftrightarrow a = 5 \\ Then , \\ p = 3, a = 5 \\ a - p = 5 - 3 \\ \Leftrightarrow a - p = 2 \end{aligned}

$\eqalign{ & \left( {x - 2} \right)\left( {x - p} \right) = {x^2} - ax + 6 \cr & {x^2} - \left( {2 + p} \right)x + 2p = {x^2} - ax + 6 \cr & {\text{Comparision the cofficients}} \cr & 2 + p = a \cr & 2p = 6 \cr & \Leftrightarrow p = 3 \cr & 2 + 3 = a \cr & \Leftrightarrow a = 5 \cr & {\text{Then , }} \cr & p = 3,{\text{ }}a = 5 \cr & a - p = 5 - 3 \cr & \Leftrightarrow a - p = 2 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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