p2+1p2=47,p2+1p2=47,{p^2} + \frac{1}{{{p^2}}} = 47{\text{,}}    then the value of p+1p" role="presentation">p+1pp+1pp + \frac{1}{p}  is?" /> p2+1p2=47,p2+1p2=47,{p^2} + \frac{1}{{{p^2}}} = 47{\text{,}}    then the value of p+1p" role="presentation">p+1pp+1pp + \frac{1}{p}  is?" /> p2+1p2=47,p2+1p2=47,{p^2} + \frac{1}{{{p^2}}} = 47{\text{,}}    then the value of p+1p" role="presentation">p+1pp+1pp + \frac{1}{p}  is?" />

If
p2+1p2=47,
   then the value of
p+1p
 is?

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  • 48
Answer:- 1
Explanation:-

Solution:
p2+1p2=47On adding 2 both sidep2+1p2+2=47+2(p+1p)2=49(p+1p)=7p+1p=7

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   then the value of
p+1p
 is?", "text": "If
p2+1p2=47,
   then the value of
p+1p
 is?", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "
Solution:
p2+1p2=47On adding 2 both sidep2+1p2+2=47+2(p+1p)2=49(p+1p)=7p+1p=7
", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "
Solution:
p2+1p2=47On adding 2 both sidep2+1p2+2=47+2(p+1p)2=49(p+1p)=7p+1p=7
", "dateCreated": "7/24/2019 10:09:12 AM" } }
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