(a+1a)2=3,(a+1a)2=3,{\left( {a + \frac{1}{a}} \right)^2} = 3{\text{,}}    the value of a3+1a3" role="presentation">a3+1a3a3+1a3{a^3} + \frac{1}{{{a^3}}}   = ?" /> (a+1a)2=3,(a+1a)2=3,{\left( {a + \frac{1}{a}} \right)^2} = 3{\text{,}}    the value of a3+1a3" role="presentation">a3+1a3a3+1a3{a^3} + \frac{1}{{{a^3}}}   = ?" /> (a+1a)2=3,(a+1a)2=3,{\left( {a + \frac{1}{a}} \right)^2} = 3{\text{,}}    the value of a3+1a3" role="presentation">a3+1a3a3+1a3{a^3} + \frac{1}{{{a^3}}}   = ?" />

If
(a+1a)2=3,
   the value of
a3+1a3
  = ?

  • 10
  • 2
    3(a+1a)
  • 3
    3(a2+1a2)
  • 41
Answer:- 1
Explanation:-

Solution:
(a+1a)2=3a+1a=3Taking cube on both sides a3+1a3+3.a.1a(a+1a)=33 a3+1a3+3(3)=33 a3+1a3=3333a3+1a3=0

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   the value of
a3+1a3
  = ?", "text": "If
(a+1a)2=3,
   the value of
a3+1a3
  = ?", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "
Solution:
(a+1a)2=3a+1a=3Taking cube on both sides a3+1a3+3.a.1a(a+1a)=33 a3+1a3+3(3)=33 a3+1a3=3333a3+1a3=0
", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "
Solution:
(a+1a)2=3a+1a=3Taking cube on both sides a3+1a3+3.a.1a(a+1a)=33 a3+1a3+3(3)=33 a3+1a3=3333a3+1a3=0
", "dateCreated": "7/24/2019 10:09:12 AM" } }
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