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If one pipe A can fill a tank in 20 minutes, then 5 pipes, each of 20% efficiency of A, can fill the tank in:

180 min
2100 min
320 min
425 min

Answer:- 1

Explanation:-

Solution:

Efficiency of pipe A,

\frac{100}{20}

$\frac{{100}}{{20}}$ = 5%
20% of efficiency of A = 1%
Then, efficiency of 5 such pipes = 5%.
Then,
Time taken to fill the tank =

\frac{100}{5}

$\frac{{100}}{5}$ = 20 min.

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= 5%
20% of efficiency of A = 1%
Then, efficiency of 5 such pipes = 5%.
Then,
Time taken to fill the tank =

\frac{100}{5}

$\frac{{100}}{5}$ = 20 min. ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

Efficiency of pipe A,

\frac{100}{20}

$\frac{{100}}{{20}}$ = 5%
20% of efficiency of A = 1%
Then, efficiency of 5 such pipes = 5%.
Then,
Time taken to fill the tank =

\frac{100}{5}

$\frac{{100}}{5}$ = 20 min. ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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