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A 100 m long train is going at a speed of 60 km/hr. It will cross a 140 m long railway bridge in-

13.6 sec
27.2 sec
314.4 sec
421.6 sec

Answer:- 1

Explanation:-

Solution:

\begin{aligned} Speed \\ = (60 \times \frac{5}{18}) m/sec \\ = \frac{50}{3} m/sec \\ Total distance covered \\ =  (100  + 140) m  =  240 m \\ ∴ Required time \\ = (240 \times \frac{3}{50}) sec \\ = \frac{72}{5} sec \\ =  14 .4 sec \end{aligned}

$\eqalign{ & {\text{Speed }} \cr & {\text{ = }}\left( {60 \times \frac{5}{{18}}} \right){\text{m/sec}} \cr & {\text{ = }}\frac{{50}}{3}{\text{ m/sec}} \cr & {\text{Total distance covered}} \cr & {\text{ = (100 + 140) m = 240 m}} \cr & \therefore {\text{Required time}} \cr & {\text{ = }}\left( {240 \times \frac{3}{{50}}} \right){\text{sec}} \cr & {\text{ = }}\frac{{72}}{5}{\text{sec}} \cr & {\text{ = 14}}{\text{.4 sec}} \cr}$

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", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} Speed \\ = (60 \times \frac{5}{18}) m/sec \\ = \frac{50}{3} m/sec \\ Total distance covered \\ =  (100  + 140) m  =  240 m \\ ∴ Required time \\ = (240 \times \frac{3}{50}) sec \\ = \frac{72}{5} sec \\ =  14 .4 sec \end{aligned}

$\eqalign{ & {\text{Speed }} \cr & {\text{ = }}\left( {60 \times \frac{5}{{18}}} \right){\text{m/sec}} \cr & {\text{ = }}\frac{{50}}{3}{\text{ m/sec}} \cr & {\text{Total distance covered}} \cr & {\text{ = (100 + 140) m = 240 m}} \cr & \therefore {\text{Required time}} \cr & {\text{ = }}\left( {240 \times \frac{3}{{50}}} \right){\text{sec}} \cr & {\text{ = }}\frac{{72}}{5}{\text{sec}} \cr & {\text{ = 14}}{\text{.4 sec}} \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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