The LCM of23,35,47,913 is = ?The LCM of23,35,47,913 is = ?\eqalign{ & {\text{The LCM of}} \cr & \frac{2}{3}{\text{,}}\frac{3}{5}{\text{,}}\frac{4}{7},\frac{9}{{13}}{\text{ is = ?}} \cr} " /> The LCM of23,35,47,913 is = ?The LCM of23,35,47,913 is = ?\eqalign{ & {\text{The LCM of}} \cr & \frac{2}{3}{\text{,}}\frac{3}{5}{\text{,}}\frac{4}{7},\frac{9}{{13}}{\text{ is = ?}} \cr} " /> The LCM of23,35,47,913 is = ?The LCM of23,35,47,913 is = ?\eqalign{ & {\text{The LCM of}} \cr & \frac{2}{3}{\text{,}}\frac{3}{5}{\text{,}}\frac{4}{7},\frac{9}{{13}}{\text{ is = ?}} \cr} " />

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$\begin{aligned} The LCM of \\ \frac{2}{3}, \frac{3}{5}, \frac{4}{7}, \frac{9}{13} is = ? \end{aligned}$ $\eqalign{ & {\text{The LCM of}} \cr & \frac{2}{3}{\text{,}}\frac{3}{5}{\text{,}}\frac{4}{7},\frac{9}{{13}}{\text{ is = ?}} \cr}$

136
2¹/₃₆
3¹/₁₃₆₅
4¹²/₄₅₅

Answer:- 1

Explanation:-

Solution:

\begin{aligned} Required LCM \\ = \frac{LCM of 2,3,4,9}{HCF of 3,5,7,13} \\ = \frac{36}{1} \\ = 36 \end{aligned}

$\eqalign{ & {\text{Required LCM}} \cr & = \frac{{{\text{LCM of 2,3,4,9}}}}{{{\text{HCF of 3,5,7,13}}}} \cr & = \frac{{36}}{1} \cr & = 36 \cr}$

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", "text": "

\begin{aligned} The LCM of \\ \frac{2}{3}, \frac{3}{5}, \frac{4}{7}, \frac{9}{13} is  =  ? \end{aligned}

$\eqalign{ & {\text{The LCM of}} \cr & \frac{2}{3}{\text{,}}\frac{3}{5}{\text{,}}\frac{4}{7},\frac{9}{{13}}{\text{ is = ?}} \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} Required LCM \\ = \frac{LCM of 2,3,4,9}{HCF of 3,5,7,13} \\ = \frac{36}{1} \\ = 36 \end{aligned}

$\eqalign{ & {\text{Required LCM}} \cr & = \frac{{{\text{LCM of 2,3,4,9}}}}{{{\text{HCF of 3,5,7,13}}}} \cr & = \frac{{36}}{1} \cr & = 36 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} Required LCM \\ = \frac{LCM of 2,3,4,9}{HCF of 3,5,7,13} \\ = \frac{36}{1} \\ = 36 \end{aligned}

$\eqalign{ & {\text{Required LCM}} \cr & = \frac{{{\text{LCM of 2,3,4,9}}}}{{{\text{HCF of 3,5,7,13}}}} \cr & = \frac{{36}}{1} \cr & = 36 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }