3–√ = 1.7321,3 = 1.7321,\sqrt 3 {\text{ = 1}}{\text{.7321,}}   then the value of 192−1248−75," role="presentation">192−−−√−1248−−√−75−−√,192−1248−75,\sqrt {192} - \frac{1}{2}\sqrt {48} - \sqrt {75} {\text{,}}     correct to 3 place of decimal, is = ?" /> 3–√ = 1.7321,3 = 1.7321,\sqrt 3 {\text{ = 1}}{\text{.7321,}}   then the value of 192−1248−75," role="presentation">192−−−√−1248−−√−75−−√,192−1248−75,\sqrt {192} - \frac{1}{2}\sqrt {48} - \sqrt {75} {\text{,}}     correct to 3 place of decimal, is = ?" /> 3–√ = 1.7321,3 = 1.7321,\sqrt 3 {\text{ = 1}}{\text{.7321,}}   then the value of 192−1248−75," role="presentation">192−−−√−1248−−√−75−−√,192−1248−75,\sqrt {192} - \frac{1}{2}\sqrt {48} - \sqrt {75} {\text{,}}     correct to 3 place of decimal, is = ?" />

If
3 = 1.7321,
  then the value of
192124875,
    correct to 3 place of decimal, is = ?

  • 18.661
  • 24.331
  • 31.732
  • 4-1.732
Answer:- 1
Explanation:-

Solution:
According to question192124875834235383235331.732

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  then the value of
192124875,
    correct to 3 place of decimal, is = ?", "text": "If
3 = 1.7321,
  then the value of
192124875,
    correct to 3 place of decimal, is = ?", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "
Solution:
According to question192124875834235383235331.732
", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "
Solution:
According to question192124875834235383235331.732
", "dateCreated": "7/24/2019 10:09:12 AM" } }
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