x=3–√ + 2–√,x=3 + 2,x = \sqrt 3 {\text{ + }}\sqrt 2 {\text{,}}   then the value of x3−1x3" role="presentation">x3−1x3x3−1x3{x^3} - \frac{1}{{{x^3}}}   is?" /> x=3–√ + 2–√,x=3 + 2,x = \sqrt 3 {\text{ + }}\sqrt 2 {\text{,}}   then the value of x3−1x3" role="presentation">x3−1x3x3−1x3{x^3} - \frac{1}{{{x^3}}}   is?" /> x=3–√ + 2–√,x=3 + 2,x = \sqrt 3 {\text{ + }}\sqrt 2 {\text{,}}   then the value of x3−1x3" role="presentation">x3−1x3x3−1x3{x^3} - \frac{1}{{{x^3}}}   is?" />

If
x=3 + 2,
  then the value of
x31x3
  is?

  • 1
    102
  • 2
    142
  • 3
    222
  • 4
    82
Answer:- 1
Explanation:-

Solution:
x=3+21x=13+2×32321x=32x31x3=[x1x]3+3×x×1x(x1x)=(3+23+2)3+3(3+23+2)=(22)3+3(22)=162+62=222

Post your Comments

Your comments will be displayed only after manual approval.

  then the value of
x31x3
  is?", "text": "If
x=3 + 2,
  then the value of
x31x3
  is?", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "
Solution:
x=3+21x=13+2×32321x=32x31x3=[x1x]3+3×x×1x(x1x)=(3+23+2)3+3(3+23+2)=(22)3+3(22)=162+62=222
", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "
Solution:
x=3+21x=13+2×32321x=32x31x3=[x1x]3+3×x×1x(x1x)=(3+23+2)3+3(3+23+2)=(22)3+3(22)=162+62=222
", "dateCreated": "7/24/2019 10:09:12 AM" } }
Test
Classes
E-Book