India’s No.1 Educational Platform For UPSC,PSC And All Competitive Exam

Download Our App

Given that 10^0.48 = x, 10^0.70 = y and x^z = y², then the value of z is close to:

11.45
21.88
32.9
43.7

Answer:- 1

Explanation:-

Solution:

\begin{aligned} x^{2} = y^{2} \Leftrightarrow 10^{(0.48 z)} = 10^{2 \times 0.70} = 10^{1.40} \\ \Rightarrow 0.48 z = 1.40 \\ \Rightarrow z = \frac{140}{48} = \frac{35}{12} = 2.9 (approx) \end{aligned}

$\eqalign{ & {x^2} = {y^2} \Leftrightarrow {10^{\left( {0.48z} \right)}} = {10^{2 \times 0.70}} = {10^{1.40}} \cr & \Rightarrow 0.48z = 1.40 \cr & \Rightarrow z = \frac{{140}}{{48}} = \frac{{35}}{{12}} = 2.9({\text{approx}}) \cr}$

Workspace Report

Post your Comments

", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} x^{2} = y^{2} \Leftrightarrow 10^{(0.48 z)} = 10^{2 \times 0.70} = 10^{1.40} \\ \Rightarrow 0.48 z = 1.40 \\ \Rightarrow z = \frac{140}{48} = \frac{35}{12} = 2.9 (approx) \end{aligned}

$\eqalign{ & {x^2} = {y^2} \Leftrightarrow {10^{\left( {0.48z} \right)}} = {10^{2 \times 0.70}} = {10^{1.40}} \cr & \Rightarrow 0.48z = 1.40 \cr & \Rightarrow z = \frac{{140}}{{48}} = \frac{{35}}{{12}} = 2.9({\text{approx}}) \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

Test

Classes

E-Book