The value of1(216)−23 + 1(256)−34 + 1(32)−15 is = ?The value of1(216)−23 + 1(256)−34 + 1(32)−15 is = ?\eqalign{ & {\text{The value of}} \cr & \frac{1}{{{{\left( {216} \right)}^{ - \frac{2}{3}}}}}{\text{ + }}\frac{1}{{{{\left( {256} \right)}^{ - \frac{3}{4}}}}}{\text{ + }}\frac{1}{{{{\left( {32} \right)}^{ - \frac{1}{5}}}}}{\text{ is = ?}} \cr} " /> The value of1(216)−23 + 1(256)−34 + 1(32)−15 is = ?The value of1(216)−23 + 1(256)−34 + 1(32)−15 is = ?\eqalign{ & {\text{The value of}} \cr & \frac{1}{{{{\left( {216} \right)}^{ - \frac{2}{3}}}}}{\text{ + }}\frac{1}{{{{\left( {256} \right)}^{ - \frac{3}{4}}}}}{\text{ + }}\frac{1}{{{{\left( {32} \right)}^{ - \frac{1}{5}}}}}{\text{ is = ?}} \cr} " /> The value of1(216)−23 + 1(256)−34 + 1(32)−15 is = ?The value of1(216)−23 + 1(256)−34 + 1(32)−15 is = ?\eqalign{ & {\text{The value of}} \cr & \frac{1}{{{{\left( {216} \right)}^{ - \frac{2}{3}}}}}{\text{ + }}\frac{1}{{{{\left( {256} \right)}^{ - \frac{3}{4}}}}}{\text{ + }}\frac{1}{{{{\left( {32} \right)}^{ - \frac{1}{5}}}}}{\text{ is = ?}} \cr} " />

The value of1(216)23 + 1(256)34 + 1(32)15 is = ?

  • 1102
  • 2105
  • 3107
  • 4109
Answer:- 1
Explanation:-

Solution:
1(216)23 + 1(256)34 + 1(32)15=1(63)23 + 1(44)34 + 1(25)15=163×(2)3 + 144×(3)4+125×(1)5=162 + 143 + 121=(62+43+21)=(36+64+2)=102

Post your Comments

Your comments will be displayed only after manual approval.

", "text": "
The value of1(216)23 + 1(256)34 + 1(32)15 is = ?
", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "
Solution:
1(216)23 + 1(256)34 + 1(32)15=1(63)23 + 1(44)34 + 1(25)15=163×(2)3 + 144×(3)4+125×(1)5=162 + 143 + 121=(62+43+21)=(36+64+2)=102
", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "
Solution:
1(216)23 + 1(256)34 + 1(32)15=1(63)23 + 1(44)34 + 1(25)15=163×(2)3 + 144×(3)4+125×(1)5=162 + 143 + 121=(62+43+21)=(36+64+2)=102
", "dateCreated": "7/24/2019 10:09:12 AM" } }
Test
Classes
E-Book