India’s No.1 Educational Platform For UPSC,PSC And All Competitive Exam

Download Our App

A bag contains 6 black and 8 white balls. One ball is drawn at random. What is the probability that the ball drawn is white?

1³/₄
2⁴/₇
3¹/₈
4³/₇

Answer:- 1

Explanation:-

Solution:

\begin{aligned} Let number of balls \\ = (6 + 8) \\ = 14. \\ Number of white balls = 8. \\ P (drawing a whiteall) \\ = \frac{8}{14} = \frac{4}{7} \end{aligned}

$\eqalign{ & {\text{Let}}\,{\text{number}}\,{\text{of}}\,{\text{balls}} \cr & = \left( {6 + 8} \right) \cr & = 14. \cr & {\text{Number}}\,{\text{of}}\,{\text{white}}\,{\text{balls}} = 8. \cr & P\left( {{\text{drawing}}\,{\text{a}}\,{\text{whiteall}}} \right) \cr & = \frac{8}{{14}} = \frac{4}{7} \cr}$

Workspace Report

Post your Comments

", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} Let number of balls \\ = (6 + 8) \\ = 14. \\ Number of white balls = 8. \\ P (drawing a whiteall) \\ = \frac{8}{14} = \frac{4}{7} \end{aligned}

$\eqalign{ & {\text{Let}}\,{\text{number}}\,{\text{of}}\,{\text{balls}} \cr & = \left( {6 + 8} \right) \cr & = 14. \cr & {\text{Number}}\,{\text{of}}\,{\text{white}}\,{\text{balls}} = 8. \cr & P\left( {{\text{drawing}}\,{\text{a}}\,{\text{whiteall}}} \right) \cr & = \frac{8}{{14}} = \frac{4}{7} \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

Test

Classes

E-Book