A student got twice as many sums wrong as he got right. If he attempted 48 sums in all, how many did he solve correctly ?
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Answer:- 1
Explanation:-

Solution:
Suppose the boy got x sums right and 2x sums wrong.
Then, x + 2x = 48 ⇔ 3x = 48 ⇔ x = 16.

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